The coolant reservoir, also known as the coolant overflow tank, is a crucial component of a vehicle’s cooling system. It’s responsible for storing excess coolant when the engine heats up, and releasing it back into the radiator when the engine cools down. Unfortunately, like any other automotive component, the coolant reservoir can fail, leading to cracks and leaks. In this article, we’ll explore what causes the coolant reservoir to crack, how to fix it, and the replacement cost.
What Causes the Coolant Reservoir to Crack?
- Age and wear: Over time, the plastic material of the coolant reservoir can become brittle and prone to cracking due to exposure to heat and pressure.
- Overheating: When an engine overheats, it puts additional stress on the coolant reservoir. The excess heat causes the plastic to expand and contract, eventually leading to cracks.
- Poor maintenance: A lack of regular maintenance can lead to low coolant levels, which can cause the reservoir to crack due to increased pressure.
How to Fix a Cracked Coolant Reservoir
The first step in fixing a cracked coolant reservoir is to determine the location and severity of the crack. If the crack is small, you can use an epoxy resin or a sealant to repair it. However, if the crack is large or the reservoir is severely damaged, replacement is often the best option.
Replacement Cost
The cost of replacing a coolant reservoir varies depending on the make and model of your vehicle, as well as the location of the reservoir. On average, the cost of a new coolant reservoir ranges from $50 to $150, and labor costs can range from $100 to $200.
Call to Action
If you notice any signs of a cracked coolant reservoir, such as low coolant levels, engine overheating, or visible leaks, it’s important to have it inspected and repaired as soon as possible. At Advanced Auto Care -Vista, our expert technicians can diagnose and fix any issues with your vehicle’s cooling system. Give us a call today to schedule an appointment and ensure your vehicle stays cool and safe on the road.